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Question

If the class intervals are 1019,2029,3039,... then the upper limit of the first class-interval is

A
19.5
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B
19
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C
20
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D
None of these
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Solution

The correct option is A 19.5
1019,2029,3039,...
Here the class intervals are not continuous. To make them continuous take the mean of upper limit of first class and lower limit of second class.
Mean =19+202=19.5, which gives the upper limit of first class and lower limit of second class for the continuous class intervals.

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