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Question

If the concentration of OH ions in the reaction:
Fe(OH)3(s)Fe3+(aq)+3OH(aq.)
is decreased by 1/4 times, then equilibrium concentration of Fe3+ will increase by:

A
64 times
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B
4 times
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C
8 times
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D
16 times
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Solution

The correct option is A 64 times
If the concentration of OH ions in the reaction:
Fe(OH)3(s)Fe3+(aq)+3OH(aq.)
is decreased by 1/4 times, then equilibrium concentration of Fe3+ will increase by 64 times.
K=[Fe3+]i[OH]3i....(1)
K=[Fe3+]f[OH]3f....(2)
[Fe3+]i and [OH]3i are the inital concentrations.
[Fe3+]f and [OH]3f are the final concentrations.
From (1) and (2)

[Fe3+]i[OH]3i=[Fe3+]f[OH]3f.....(3)
The concentration of OH ions is decreased by 1/4 times
[OH]f=[OH]i4....(4)
Substitute equation (4) in equation (3)
[Fe3+]i[OH]3i=[Fe3+]f([OH]i4)3
[Fe3+]i=[Fe3+]f(14)3
43×[Fe3+]i=[Fe3+]f
64×[Fe3+]i=[Fe3+]f

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