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Question

If the coordinates of a point on the y-axis which is equidistant from the points (13,2) and (12,3) is (p,q), then find the value of p+q.

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Solution

Given Co-ordinates of a point on y -axis equidistant from the points (13,2) and (12, -3) is (p,q)
To find P+q
Sol - the point lies on y-axis i.e. us of the
form (0,y)
p=0
(0,q) is equidistant from (13,2) and (12,-3)
(013)2+(q2)2=(012)2+(q+3)2
(013)2+(q2)2=(012)2+(q+3)2
169+q2+44q=144+q2+9+6q
1734q=153+6q
173153=6q+44q
20=10qv
2=q
p+q=0+2=2

1125824_1103686_ans_3e1f7582517449798a589d55be8b6280.jpg

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