Question

If the density of a liquid is 20 g cm^-3, height is 4 cm and the gravitational field strength is 10 N kg^-1, the pressure at the bottom of the liquid is

• A. 8 Pascal
• B. 50 Pascal
• C. 8000 Pascal
• D. 2 Pascal

Answer 1

The correct option is C

8000 Pascal

We apply the formula P = $\rho gh$

We get P = 20 g cm^-3,* 4 cm * 10 N kg^-1,

Since all the answers are in Pascals, we need it to be in N m^-2

And for that, we will have to convert all the CGS units to MKS units.

Doing that, we find,

$\rho$ = 20 kg m^-3,

g = 10 m s^-2,

h = 0.04 m

Applying the formula P = $\rho gh$

we get,

P = 20 kg m^-3​​*10 m s^-2*0.04 m

Therefore, P = 8000 Pa