Question

# If the difference between $$(n + 1)^{th}$$ Bohr radius and $$n^{th}$$ Bohr radius is equal to the $$(n -1)^{th}$$ Bohr radius then find the value of $$n$$

A
4
B
3
C
2
D
1

Solution

## The correct option is A $$4$$Radius of $$n^{th} orbit$$ is $$r_n=n^2r_0$$ where $$r_0$$ is radius of ground state.Given that $$(n+1)^2r_0 - n^2r_0=(n-1)^2r_0$$Solving above equation will result in $$n=4$$Physics

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