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Question

If the difference between $$(n + 1)^{th}$$ Bohr radius and $$n^{th}$$ Bohr radius is equal to the $$(n -1)^{th}$$ Bohr radius then find the value of $$n$$


A
4
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B
3
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C
2
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D
1
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Solution

The correct option is A $$4$$
Radius of $$n^{th} orbit$$ is $$r_n=n^2r_0$$ where $$r_0$$ is radius of ground state.
Given that $$(n+1)^2r_0 - n^2r_0=(n-1)^2r_0$$
Solving above equation will result in $$n=4$$

Physics

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