If the distance between the foci and the distance between the directrices of the hyperbola x2a2−y2b2=1 are in the ratio 3:2, then a:b is
A
√2:1
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B
√3:√2
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C
1:2
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D
2:1
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Solution
The correct option is B√2:1 Equation of hyperbola is x2a2−y2b2=1 Distance between foci =2ae and distance between directrices =2ae According to the question, we have 2ae2a/e=32 ⇒e2=32 We know that b2=a2(e2−1) ⇒b2a2=32−1=12 ⇒ba=1√2 Therefore, required ratio a:b is √2:1.