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Question

If the efficiency of a machine is 10 % and the work done on a machine is 2000 J, then what is the work done by the machine?



A

800 J

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B

1100 J

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C

200 J

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D

1500 J

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Solution

The correct option is C

200 J


Given:
Input work done = 2000 J

Efficiency, n=10 %=0.10

n=Output workInput work 

Output work=n×Input work
=0.10×2000 J=200 J
Work done by the machine is 200 J.


Physics

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