Question

If the electrons in chromium $\left(Cr\right)$ have $m_l=+1$ and $m_s=-\frac{1}{2}$, then:

• A. The minimum number of such electrons is 3
• B. The minimum number of such electrons is 2
• C. The maximum number of such electrons is 3
• D. The maximum number of such electrons is 4

Answer 1

Answer: (B), (C)

The correct options are
B The minimum number of such electrons is 2
C The maximum number of such electrons is 3

For $Cr$,

One electron out of the six electrons each in $2p$ and $3p$ subshells have the given configuration.

But in $3d$ subshell, the orbital having $m_l=+1$ may have spin quantum number $-\frac{1}{2}\text{or}+\frac{1}{2}$

$\therefore$ The minimum and the maximum possible values are 2 and 3 respectively.