Question

# If the end correction of an open pipe is 0.8 cm then the inner radius of that pipe will be

A
13 cm
B
23 cm
C
32 cm
D
0.2 cm

Solution

## The correct option is B $$\dfrac{2}{3}$$ cmTotal end correction of open pipe $$x_t = 0.8$$ cmAs open pipe has end correction on both sides.Thus end correction on each side $$x = \dfrac{x_t}{2} = 0.4$$  cmDiameter of inner pipe $$D = \dfrac{x}{0.3} = \dfrac{0.4}{0.3}$$ cmThus radius of inner pipe  $$r = \dfrac{D}{2} = \dfrac{0.4}{2\times 0.3}$$$$\implies$$ $$r = \dfrac{2}{3}$$ cmPhysics

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