Question

If the end correction of an open pipe is 0.8 cm then the inner radius of that pipe will be

• A. $\frac{1}{3}$ cm
• B. $\frac{2}{3}$ cm
• C. $\frac{3}{2}$ cm
• D. $0.2$ cm

Answer 1

The correct option is B $\frac{2}{3}$ cm

Total end correction of open pipe $x_t=0.8$ cm

As open pipe has end correction on both sides.

Thus end correction on each side $x=\frac{x_t}{2}=0.4$ cm

Diameter of inner pipe $D=\frac{x}{0.3}=\frac{0.4}{0.3}$ cm

Thus radius of inner pipe $r=\frac{D}{2}=\frac{0.4}{2\times 0.3}$

$⟹$ $r=\frac{2}{3}$ cm