CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If the equation of base of an equilateral triangle is $$2x-y =1$$ and the vertex is$$ (-1, 2),$$ then the length of the sides of the triangle is


A
203
loader
B
203
loader
C
815
loader
D
152
loader

Solution

The correct option is A $$\displaystyle \sqrt{\frac{20}{3}}$$
Let the equilateral triangle be ABC and foot of perpendicular from A to BC is AD, then
$$ AD= |\dfrac{2(-1)-2-1}{\sqrt{2^2+1^2}}|$$ $$=\sqrt5$$
now AB $$=cosec 60^o \times AD =\dfrac{2}{\sqrt3} \times \sqrt 5 =\dfrac{\sqrt20}{\sqrt3}$$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image