CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the function f(x)=x3+bx2+ax+5 on [1,3] satisfies the conditions of Rolle's Theorem with c=2+13, then find a + b.

Open in App
Solution

f(x)=x3+bx2+ax+5
f(1)=f(3)
1+b+a+5=27+9b+3a+5
a+4b=13
f(x)=3x22bx+a
f(c)=0
Now c=2+13
3(2+13)2+b(2+13)+a=0
13+43+2b(6+3)3+a=0
solving the above equation
x=11
y=6
x+y=5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems for Differentiability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon