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Question

If the HCF and LCM of two numbers are 13 and 1989 respectively and one of the number is 221, determine the other number.


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Solution

Let Suppose we have two numbers a and b, then we have a rule i.e a×b=HCF(a,b)×LCM(a,b), which means that product of those two numbers is equal to the product of their LCM and HCF

Given : HCF=13andLCM=1989, a=221

so using the property, we have 221×b=13×1989

b=13×1989221

b=13×9

b=117

Hence the other number is 117


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