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Question

If the HCF of 408 and 1032 is expressible in the form 1032 m408×5, find m.

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Solution

By Euclid's division algorithm

1032=408×2+216

408=216×1+192

216=192×1+24

192=24×8+0

Since the reminder becomes 0 here, so HCF of 408 and 1032 is 24 now

1032m408×5=HCF of there number

1032m408×5=24

1032m=2064

m=2

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