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Question

If the HCF of x3343andx29x+14is(x7), then find their LCM

A
(x7)(x2)×(x2+7x+49)
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B
(x7)(x+2)×(x2+7x+49)
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C
(x+7)(x2)×(x2+7x+49)
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D
none of the above
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Solution

The correct option is A (x7)(x2)×(x2+7x+49)
x3343=x3(7)3=(x7)(x2+7x+49)x29x+14=x22x7(x2)=(x7)(x2) HCF of the polynomials (x7) Reqd. LCM==(x3343)×(x29x+14)HCF=(x7)(x2+7x+49)×(x7)(x2)(x7)=(x7)(x2)×(x2+7x+49)

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