If the heat o...

Question

If the heat of dissolution of $a n . C u S O_{4}$ and $C u S O_{4} .5 H_{2} O$ are (-15.89) kcal and 2.80 kcal respectively. Calculate the heat of hydration of $C u S O_{4}$ :

-13.09 kcal

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-18.69 kcal

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13.09 kcal

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18.69 kcal

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Solution

The correct option is D 13.09 kcal
$C u S O_{4 (s)} + a q \to C u S O_{4 (a q)} Δ H = 15.89 k c a l C u S O_{4} .5 H_{2} O_{(s)} + a q \to C u S O_{4 (a q)} Δ H = 2.80 k c a l - ---------------------------------------------------------- - C u S O_{4 (s)} + a q \to C u S O_{4} .5 H_{2} O_{(a q)} Δ H = ?$
Subtracting equation 2 from equation 1 gives 13.09 kcal.

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