If the hypotenuse of a right-angled triangle is h and it's inradius is r, then find it's area.
Let PB = BQ = r
AP = AR = b - r
CQ = CR = a - r
AR + CR = h
a + b - 2r = h
a + b = h + 2r
Area = A = rS
⇒ A = ra+b+h2
⇒ A = rh+2r+h2
⇒ A = r(h + r)