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Question

If the integral of the function e3x is g(x) and g(0)=13, then the value of  3eg(13) is 



A
1
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B
3
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C
e
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Solution

The correct option is A 1

We know that exdx=ex+c and f(ax+b)dx=F(ax+b)a+C

We have f(x)=ex and F(x)=ex.

If f(ax+b)=e3x, a=3 and b=0

f(ax+b)dx=e3x.dx

=e3x3+c=g(x)

We are given g(0)=13

c=0

Now,  3g(13)=e

Thus, 3eg(13)
=1ee
=1


Mathematics

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