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Question

# If the ionization potential of Na is 495.8 Kj mol−1, the electron affinity of CI is 349.4 kJ mol−1 and lattice energy is 776 kJ mol−1, the true statement for the formation of ionic bond in NaCl is :

A
total energy released per mole of NaCl formed is 626 kJ
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B
the ionic bond formed is unstable
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C
the total energy absorbed per mole of NaCl formed is 1125.4 kJ
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D
net energy released in this process is 629.6 J
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Solution

## The correct option is A total energy released per mole of NaCl formed is 626 kJNa→Na++e−,IE=495.8kJmol−1Cl+e−→Cl−,EA=−349.4kJmol−1Na(s)+12Cl2(g)→NaCl(s)Na++Cl−(g)→NaCl(s)ΔHf0=108+496+122−349−788=−411kJmol−1Total energy required is (108+496+122)=626kJmol−1

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