Question

If the length of E.coli DNA is 1,360 micron then what is the number of base pairs in this DNA?

• A. $4\times {10}^6$
• B. $4\times {10}^7$
• C. $4\times {10}^8$
• D. $4\times {10}^9$

Answer 1

The correct option is: C

Explanation of the correct option:

The length of E.coli DNA is 1,360 micron
= 1.36 mm
= 1.36 x ${10}^7\stackrel{\circ }{A}$

And distance between 2 base pairs = 0.34 nm = 3.4 $\stackrel{\circ }{A}$

So, total number of base pairs $1.36\times {10}^7÷\left(3.4\right)=4\times {10}^6$

$=4\times {10}^6$

Explanation of the incorrect option:

Option A: If the length of E.coli DNA is 1,360 microns then the number of base pairs in this DNA is $4\times {10}^6$

Option B: If the length of E.coli DNA is 1,360 microns then the number of base pairs in this DNA is $4\times {10}^6$

Option D: If the length of E.coli DNA is 1,360 microns then the number of base pairs in this DNA is $4\times {10}^6$

Final answer: If the length of E.coli DNA is 1,360 microns then the number of base pairs in this DNA is $4\times {10}^6$