    Question

# If the length of the chord of the parabola y2=4x whose slope is 1, is 10√2 units, then equation of the chord is

A
x=y+21
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B
4x=4y+21
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C
x=y21
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D
4y=4x+21
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Solution

## The correct option is B 4x=4y+21Let the coordinates of the end points of the chord be (t21,2t1) and (t22,2t2) ∴1=2t1+t2⇒t1+t2=2 …(1) Now, the length of the chord is 10√2=√(t1−t2)2(4+(t1+t2)2)⇒10√2=(t1−t2)√8 [From (1)]⇒t1−t2=5 …(2) From (1) and (2), t1=72 So, the coordinates of one end of the chord is (494,7) Equation of the chord is y−7=x−494 ∴4x=4y+21  Suggest Corrections  2      Similar questions
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