If the magnitude of the the Earths magnetic field at the equator is 3-3- 10-5 T - then the magnitude of the field at the poles is -

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Standard XII

Physics

Magnetic Meridian

If the magnit...

Question

If the magnitude of the the Earths magnetic field at the equator is $3.3 \times 10^{- 5} T$ , then the magnitude of the field at the poles is :

3.3 \times 10^{- 5} T

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6.6 \times 10^{- 5} T

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8.4 \times 10^{- 5} T

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2 \times 10^{- 5} T

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Solution

The correct option is B $6.6 \times 10^{- 5} T$
$B_{a x i a l} = 2 B_{e q u a t o r i a l}$
$∴ B_{p o l a r} = 2 B_{e q u a t o r i a l}$
$B_{p o l a r} = 2 \times 3.3 \times 10^{- 5}$
$B_{p o l a r} = 6.6 \times 10^{- 5} T$

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If the magnitude of the the Earths magnetic field at the equator is 3.3×10−5T , then the magnitude of the field at the poles is :

The correct option is B 6.6×10−5TBaxial=2Bequatorial∴Bpolar=2BequatorialBpolar=2×3.3×10−5Bpolar=6.6×10−5T

If the magnitude of the the Earths magnetic field at the equator is $3.3 \times 10^{- 5} T$ , then the magnitude of the field at the poles is :

The correct option is B $6.6 \times 10^{- 5} T$
$B_{a x i a l} = 2 B_{e q u a t o r i a l}$
$∴ B_{p o l a r} = 2 B_{e q u a t o r i a l}$
$B_{p o l a r} = 2 \times 3.3 \times 10^{- 5}$
$B_{p o l a r} = 6.6 \times 10^{- 5} T$