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Question

If the mean of the distribution is 62.8 and sum of frequency is 50, find p and q.
ClassFrequency
0-205
20-40P
40-6010
60-80Q
80-1007
100-1208

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Solution

Given that

mean of distribution is 62.8

sum of frequency is 50
Class020 2040 4060608080100100120
frequency5P10Q7 8

Class frequency (f)
mid point (x) fx
02051050
2040P30 30P
40601050 500
6080Q7070Q
80100790630
1001208110 880
Here
f=30+P+Q

fx=2060+30P+70Q

We have f=50

30+P+Q=50P+Q=20 __(1)

we know ¯x=fxf=(2060+30P+70Q)/50

62.8×50=2060+30P+70Q

30P+70Q=31402060=1080 __(2)

(1)×70 70P+70Q=1400
(2) 30P+70Q=1050–––––––––––––––––––
40P=320 P=8

P=8(1)P+Q=20Q=20P=208=12

Q=12

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