If the median of the data x1- x2- x3- x4- x5- x6- x7- x8 is - and x1-x2-x3-x4-x5-x6-x7-x8- then the median of x3- x4-x5-x6 is

The correct option is C α We have #160; α = x_4+x_5/2 ∴ Median of x_3, x_4, x_5, x_6 is x_4+x_5/2 = α ...

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Byju's Answer

Standard X

Mathematics

Median

If the median...

Question

If the median of the data $x_{1}, x_{2}, x_{3}, x_{4}, x_{5}, x_{6}, x_{7}, x_{8}$ is $α$ and $x_{1} < x_{2} < x_{3} < x_{4} < x_{5} < x_{6} < x_{7} < x_{8}$ , then the median of $x_{3}, x_{4}, x_{5}, x_{6}$ is

α

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\frac{α}{2}

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\frac{α}{3}

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\frac{α}{4}

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Solution

The correct option is C $α$
We have $α = \frac{x_{4} + x_{5}}{2}$
$∴$ Median of $x_{3}, x_{4}, x_{5}, x_{6}$ is $\frac{x_{4} + x_{5}}{2} = α$

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If the median of the data x1,x2,x3,x4,x5,x6,x7,x8 is α and x1<x2<x3<x4<x5<x6<x7<x8, then the median of x3,x4,x5,x6 is

The correct option is C αWe have α=x4+x52∴ Median of x3,x4,x5,x6 is x4+x52=α

If the median of the data $x_{1}, x_{2}, x_{3}, x_{4}, x_{5}, x_{6}, x_{7}, x_{8}$ is $α$ and $x_{1} < x_{2} < x_{3} < x_{4} < x_{5} < x_{6} < x_{7} < x_{8}$ , then the median of $x_{3}, x_{4}, x_{5}, x_{6}$ is

The correct option is C $α$
We have $α = \frac{x_{4} + x_{5}}{2}$
$∴$ Median of $x_{3}, x_{4}, x_{5}, x_{6}$ is $\frac{x_{4} + x_{5}}{2} = α$