If the momentum of a body is increased by 3 %, the percentage increase in its kinetic energy is :

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1.5

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Solution

The correct option is A 6
$K E = \frac{P^{2}}{2 m}$
$△ K E = 2 P △ P / 2 m$
$∴ \frac{△ K E}{K E} = 2 \frac{△ P}{P}$
$∴△ K E = 0.06 \times K E$
The percentage increase is 6 percent.

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