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Question

If the normal at the end of latus rectum of an ellipse x2a2+y2b2=1 of eccentricity e passes through one end of the minor axis then e4+e2= 
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Solution

The correct option is B  
Latus rectum =(ae,b2a)
Equation of normal is a2xaeb2yb2a=a2b2axeay=a2b2
Since it passes through (0, b) then ab=a2b21e2=e21e2=e4 

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