If the number of observations ‘n’ in a set of data is even, then the median value is given by ____.

\frac{n}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{n + 1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{n + 2}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

average of

\frac{n}{2}

and

\frac{n}{2} + 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D average of $\frac{n}{2}$ and $\frac{n}{2} + 1$
The observation that lies in the middle of a set of observations (after arranging in an ascending or descending order) is called the median of the data.

If the number of observations ‘n’ in a set of data is odd, then median is given by average of $\frac{n}{2}$ and $\frac{n}{2} + 1$ values.

Suggest Corrections

Similar questions

^{2 n} C_{0},^{2 n} C_{1},^{2 n} C_{2}, . . . .,^{2 n} C_{n}

n

^{2 n} C_{1} +^{2 n} C_{3} +^{2 n} C_{5} + . . . . . +^{2 n} C_{n - 1} = 2^{2 n - 1}

^{2 n} C_{1} +^{2 n} C_{3} +^{2 n} C_{5} + . . . . . +^{2 n} C_{n - 1} = 2^{2 n - 2}

^{2 n} C_{2} +^{2 n} C_{4} +^{2 n} C_{6} + \dots +^{2 n} C_{2 n} = 511

^{n} C_{0} -^{n} C_{1} 3^{1} +^{n} C_{2} 3^{2} + \dots + (- 1)^{n}^{n} c_{n} 3^{n}

1^{2} + 3^{2} + 5^{2} \dots + (2 n - 1)^{2} = \frac{n}{x} (2 n - 1) (2 n + 1)

n \in N

x

(n + 2) .^{n} C_{0} . 2^{n + 1} - (n + 1)

^{n} C_{1}

2^{n} + n

^{n} C_{2}

2^{n - 1} +

= k (n + 1)

k

Join BYJU'S Learning Program