If the number of observations ‘n’ in a set of data is odd, then the median is given by ____.

average of

\frac{n}{2}

and

\frac{n}{2} + 1

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\frac{n}{2}

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\frac{n + 1}{2}

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\frac{n + 2}{2}

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Solution

The correct option is C $\frac{n + 1}{2}$
The observation that lies in the middle of a set of observations (after arranging in an ascending or descending order) is called the median of the data.

If the number of observations ‘n’ in a set of data is odd, then median is given by $\frac{n + 1}{2}$

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Similar questions

(1 + x)^{n} = n \sum r = 0^{n} C_{r} x^{n},

\frac{C_{0}}{1 \cdot 2} 2^{2} + \frac{C_{1}}{2 \cdot 3} 2^{3} + \frac{C_{2}}{3 \cdot 4} 2^{4} + \dots + \frac{C_{n}}{(n + 1) (n + 2)} 2^{n + 2}

\frac{^{n} C_{0}}{2^{n}} + 2. \frac{^{n} C_{1}}{2^{n}} + 3. \frac{^{n} C_{2}}{2^{n}} + \dots . (n + 1) \frac{^{n} C_{n}}{2^{n}} = 16

n

2^{n} - (n - 1) 2^{n - 2} + \frac{(n - 2) (n - 3)}{⌊ 2} - \frac{(n - 3) (n - 4) (n - 5)}{⌊ 3} 2^{n - 6} + . . . . .;

3

1 - (n - 1) + \frac{(n - 2) (n - 2)}{⌊ 2} - \frac{(n - 3) (n - 4) (n - 5)}{⌊ 3} + . . . . = (- 1)^{n}

n

\frac{C_{0}}{1 \cdot 2} + \frac{C_{1}}{2 \cdot 3} + \frac{C_{2}}{3 \cdot 4} + \dots

C_{r} =^{n} C_{r}

0, 1, 2, 3, \dots, n

^{n} C_{0},^{n} C_{1},^{n} C_{2}, \dots,^{n} C_{n}

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