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Question

If the numbers 1,2,3 and 4 are written separately on four slips of paper. The slips are put in a box and mixed thoroughly. A person draws two slips from the box, one after other, without replacement, then the odds against the number 1 on the first slip is

A
3.0
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B
3
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C
03
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D
3.00
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Solution

The sample space of the experiment is
S={(1,2),(1,3),(1,4),(2,1),(2,3),(2,4), (3,1),(3,2),(3,4),(4,1),(4,2),(4,3)}

Let A be event for number 1 on the first slip
number of elements in A is 3
P(A)=312=14
P(¯¯¯¯A)=34
odds against A=P(¯¯¯¯A)P(A)=3414=3

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