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Question

If the numbers 3, 5, 7, 4 have frequencies x, x+4, x3, x+8 with their arithmetic mean of 4, then x will be:

A
53
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B
23
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C
113
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D
74
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Solution

The correct option is A 53
Given:
xi3574fixx+4x3x+8
xifi=3x+5(x+4)+7(x3)+4(x+8)=3x+5x+20+7x21+4x+32=19x+31 (i)
and fi=x+x+4+x3+x+8=4x+9 (ii)
Given Mean fixifi=4
19x+314x+9=4 [From Eqs.(i) and (ii)]

19x+31=16x+363x=5 x=53

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