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Question

If the observed dipole moment of HF is 1.944 D and the bond length of HF is 90 pm. Find the % covalent character of HF.

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Solution

Percentage ionic character=observed dipole moment (in D)4.8×bond length (in A)×100=1.9444.8×0.9×100=45%

Therefore, the % covalent character = 55%

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