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Question
If the PE of a Bohr's hydrogen atom in the ground state is zero, then its total energy in the first excited state will be :
If the PE of a Bohr's hydrogen atom in the ground state is zero, then its total energy in the first excited state will be :
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Solution
The correct option is A 23.8eV
PE=−27.2eV if its taken as 0, all other energies are increased by 27.2eVTE of first excited state=−3.4eV, which becomes 23.8eV. Hence answer is option D
PE=−27.2eV if its taken as 0, all other energies are increased by 27.2eV
TE of first excited state=−3.4eV, which becomes 23.8eV. Hence answer is option D
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