Question

If the plane $7x+11y+13z=3003$ meets the coordinate axes in $A,B,C$, then centroid of the triangle $ABC$ is

• A. $(143,91,77)$
• B. $(143,77,91)$
• C. $(91,143,77)$
• D. $(143,66,91)$

Answer 1

Answer: (A)

$(143,91,77)$

Given equation of plane is $7x+11y+13z=3003$.

The plane meets the coordinate axes on the points,
$A(429,0,0),B(0,273,0)C(0,0,231)$
Hence, the coordinates of the centroid are,
$(\frac{429}{3},\frac{273}{3},\frac{231}{3})$ $=(143,91,77)$