If the point -2k - 3- k - 2- lies on the line 2x - 3y - 15 - 0- find the value of k- k- -15-7k- -13-7k- -15-7k- -13-7

The correct option is A k= 15/7Since the point (2k 3, k + 2) lies on the line 2x + 3y + 15 = 0, 2(2k 3) + 3 (k + 2) + 15 = 0 ⇒ 4k 6 + 3k + 6 + 15 = ...

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Standard VIII

Mathematics

Linear equation in one variable

If the point ...

Question

If the point (2k – 3, k + 2) lies on the line 2x + 3y + 15 = 0, find the value of k.

k = \frac{- 15}{7}

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k = \frac{- 13}{7}

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k = \frac{15}{7}

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k = \frac{13}{7}

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Solution

The correct option is A $k = \frac{- 15}{7}$
Since the point (2k - 3, k + 2) lies on the line 2x + 3y + 15 = 0,

$2 (2 k - 3) + 3 (k + 2) + 15 = 0$

$\Rightarrow 4 k - 6 + 3 k + 6 + 15 = 0$

$\Rightarrow 7 k = - 15 \Rightarrow k = \frac{- 15}{7}$

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Similar questions

Q. Find the value of k for which each of the following system of equations have infinitely many solutions :

2 x - 3 y = 7 (k + 2) x - (2 k + 1) y = 3 (2 k - 1)

If the point (2k – 3, k + 2) lies on the line 2x + 3y + 15 = 0, find the value of k.

Q. If the points (2k-3, k+2) lies on the line

2 x + 3 y + 15 = 0

, find the value of k

If the point $(2 k - 3, k + 2)$ lies on the line $2 x + 3 y + 15 = 0,$ find the value of $k$ .

If the point (2k – 3, k + 2) lies on the line 2x + 3y + 15 = 0, find the value of k.

The correct option is A k=−157Since the point (2k - 3, k + 2) lies on the line 2x + 3y + 15 = 0, 2(2k−3)+3(k+2)+15=0 ⇒4k−6+3k+6+15=0 ⇒7k=−15⇒k=−157

The correct option is A $k = \frac{- 15}{7}$
Since the point (2k - 3, k + 2) lies on the line 2x + 3y + 15 = 0,

$2 (2 k - 3) + 3 (k + 2) + 15 = 0$

$\Rightarrow 4 k - 6 + 3 k + 6 + 15 = 0$

$\Rightarrow 7 k = - 15 \Rightarrow k = \frac{- 15}{7}$