If the point P 8- a lies on the line x-4-y-5-1- then find the value of a-A- 15B- -15C- -4D- -5

The correct option is D 5 If P(8, a) lies on the line x/4+y/5=1 then its coordinates must satisfy the equation of the line. Thus, 8/4+a/5=1 2+a/5=1 a/5= 1 a = ...

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Byju's Answer

Standard IX

Mathematics

Representing Equation on Cartesian Plane

If the point ...

Question

If the point P(8, a) lies on the line $\frac{x}{4} + \frac{y}{5} = 1$ , then find the value of a.

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-15

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-4

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-5

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Solution

The correct option is D
-5

If P(8, a) lies on the line $\frac{x}{4} + \frac{y}{5} = 1$

then its coordinates must satisfy the equation of the line.

Thus, $\frac{8}{4} + \frac{a}{5} = 1$

$2 + \frac{a}{5} = 1$

$\frac{a}{5} = - 1$

a = -5

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If the point P(8, a) lies on the line x4+y5=1, then find the value of a.

The correct option is D -5 If P(8, a) lies on the line x4+y5=1 then its coordinates must satisfy the equation of the line. Thus, 84+a5=1 2+a5=1 a5=−1 a = -5

If the point P(8, a) lies on the line $\frac{x}{4} + \frac{y}{5} = 1$ , then find the value of a.

The correct option is D
-5

If P(8, a) lies on the line $\frac{x}{4} + \frac{y}{5} = 1$

then its coordinates must satisfy the equation of the line.

Thus, $\frac{8}{4} + \frac{a}{5} = 1$

$2 + \frac{a}{5} = 1$

$\frac{a}{5} = - 1$

a = -5