If the points (2k-3, k+2) lies on the line $2 x + 3 y + 15 = 0$ , find the value of k

k = \frac{- 15}{7}

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k = \frac{- 13}{7}

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k = \frac{15}{7}

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k = \frac{13}{7}

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Solution

The correct option is A $k = \frac{- 15}{7}$

$(2 k - 3, k + 2)$ lies on the line $2 x + 3 y + 15 = 0$
$\Rightarrow 2 (2 k - 3) + 3 (k + 2) + 15 = 0$
$\Rightarrow 4 k - 6 + 3 k + 6 + 15 = 0$
$\Rightarrow 7 k + 15 = 0 \Rightarrow k = \frac{- 15}{7}$

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