Question

If the potential difference applied across X- ray tube is V volt, then minimum wavelength of the emitted X-rays will be approximately:

• A. $\frac{1227}{V}{A}^o$
• B. $\frac{1240}{V}{A}^o$
• C. $\frac{2400}{V}{A}^o$
• D. $\frac{12400}{V}{A}^o$

Answer 1

The correct option is D $\frac{12400}{V}{A}^o$

As we know,

${\lambda }_{min}=\frac{hc}{eV}=\frac{6.6{\times }^{-34}}{\times }3\times {10}^{8}1.6\times {10}^{-19}V=\frac{12375}{V}\approx \frac{12400}{V}{A}^o$