If the product sin1 - sin3 - sin5 - sin7 - sin89 - - 12n- then find the value of n-

sin1^∘sin 3^∘sin 5^∘.........sin 89^∘=12^n ⇒sin 1^∘sin 2^∘sin 3^∘.....sin 88^∘sin 89^∘sin 2^∘sin 4^∘sin 6^∘.....sin 88^∘=12^n ⇒sin 1^∘sin 89^∘sin ...

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First Derivative Test for Local Maximum

If the produc...

Question

If the product $(sin 1^{\circ}) (sin 3^{\circ}) (sin 5^{\circ}) (sin 7^{\circ}) . . . . . . . . . (sin 89^{\circ}) = \frac{1}{2^{n}},$ then find the value of n.

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Solution

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