Question

# If the radius of the 3rd Bohr orbit of hydrogen is r, then the wavelength of an electron in the 6th orbit of a hydrogen atom is equal to6πr2πr4πr312πr

Solution

## The correct option is C 4πr3According to de-Broglie, circumference of the circular orbit must be an integral number of wavelength. Thus we can write, 2πrn=nλn ⇒λ6 =2πr66                        =2π×36r06      ( rn=n2a0z)            =2π×(4×9)r0(2×3)            =4π×32r03            =4πr3     (r3=9r)

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