CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If the radius of the 3rd Bohr orbit of hydrogen is r, then the wavelength of an electron in the 6th orbit of a hydrogen atom is equal to
  1. 6πr
  2. 2πr
  3. 4πr3
  4. 12πr


Solution

The correct option is C 4πr3
According to de-Broglie, circumference of the circular orbit must be an integral number of wavelength.
Thus we can write,
2πrn=nλn
λ6 =2πr66            
           =2π×36r06      ( rn=n2a0z)
           =2π×(4×9)r0(2×3)
           =4π×32r03
           =4πr3     (r3=9r)

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image