If the radius of the base of a right circular cone is halved, keeping the height same, then the ratio of the volume of the reduced cone to that of the original cone is
Radius of the base is r, and the height of the original cone is h.
Volume of the original cone (V1)=13πr2h
When cone reduced then,
Volume of the reduced cone (V2)=13π(r2)2h
This is the required solution.