If the refractive index of a material of equilateral prism is √3, then angle of minimum deviation of the prism is
60∘
A=60∘,n=√3n=sin(A+δ2)sinA2
where n is the refractive index, δm is the angle of minimum deviation, A is the prism angle
⇒sin(A+δ2)=√32A+δ2=60∘⇒δ=60∘