If the roots of the equation x3−ax2+bx−c=0 are three consecutive integers, then what is the smallest possible value of b?
The correct option is B -1
Let roots are (n - 1), n and (n + 1)
Sum of products of roots taken two at a time = b
The value of b will be minimum when the value of n2 is minimum i.e., n2=0
Hence, minimum value of b = -1.