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Question

If the roots of z3+iz2+2i = 0 represent the vertices of a triangle in the argand plane, then its area is


  1. 2

  2. 4


Solution

The correct option is A

2


z3+iz2+2i=0 (zi)(z2+2iz2) =0

z = i,  2i±4i2+82

z = i, 1-i, -1-i

∴ area of triangle with vertices (0,1), (1, -1), (-1, -1)

12  ∣ ∣011111111∣ ∣  = 2

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