Question

If the sides of a rectangle are $(x^2-x-2)$ and $(x^2+x-2)$, find the area of the rectangle.

Answer: $x^4-x^2+4x-4$

• A. True
• B. False

Answer 1

The correct option is B False

Area of rectangle $=$ product of sides

$(x^2-x-2)(x^2+x-2)$

$=\left[\right(x^2-2)-x]\left[\right(x^2-2)+x]$

$=(x^2-2{)}^2-x^2$

$=x^4-4x^2+4-x^2$

$=x^4-5x^2+4$

This doesn't match with the answer.

So, FALSE