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Question

If the sides of a triangle are proportional to the cosines of the opposite angles then the triangle is

A
right angled
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B
equilateral
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C
obtuse angled
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D
none of these
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Solution

The correct option is B equilateral
Given, cosAcosB=ab
cosAcosB=sinAsinB
cosAsinB=sinAcosB
sin(AB)=0
A=B.
Similarly, cosBcosC=bc
cosBcosC=sinBsinC
sin(BC)=0
B=C
But , A=B
Hence, A=B=C
Hence equilateral triangle.

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