Question

If the slope of the line joining the points P(-3,-2) and Q(k,0) is $\frac{4}{14}$, then find k.

• A. $\frac{1}{2}$
• B. -3
• C. 4
• D. 3

Answer 1

The correct option is C 4

$x_1=-3,x_2=k,y_1=-2\&y_2=0$
Slope, $m=\frac{y_2-y_1}{x_2-x_1}$
$\frac{4}{14}=\frac{0-(-2)}{k-(-3)}$
$\frac{2}{7}=\frac{2}{k+3}2k+6=142k=8\therefore k=4$