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Question

If the speed of the particle is v=8t33t2+2 m/s, the distance of the particle as a function of time t is 
  1. 2t42t3+2t m
  2. t4t3+2t m
  3. 2t4t3+2t m
  4. 2t4t3+2 m


Solution

The correct option is C 2t4t3+2t m
Given, the speed of the particle is v(t)=8t33t2+2
So, the distance as a function of time is given as
v(t)dt
 S=(8t33t2+2)dt=2t4t3+2t m

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