If the square of twice a number is 9 more than thrice the square of the given number, then the number can be .

3 or -3

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4 or -4

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5 or -5

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6 or -6

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Solution

The correct option is A 3 or -3
Let the number be $x$ .
$Square of twice the number = (2 x)^{2} = 4 x^{2}$
$Three times the square of the number = 3 x^{2}$
Given, square of twice the number is 9 more than three times the square of the number.
$\Rightarrow 4 x^{2} = 3 x^{2} + 9$
$\Rightarrow x^{2} - 9 = 0$
$\Rightarrow x^{2} = 9$
$\Rightarrow x = \pm 3$

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If the square of twice a number is 9 more than thrice the square of the given number, then the number can be .

The correct option is A 3 or -3Let the number be x. Square of twice the number=(2x)2=4x2 Three times the square of the number=3x2 Given, square of twice the number is 9 more than three times the square of the number. ⇒4x2=3x2+9 ⇒x2−9=0 ⇒x2=9 ⇒x=±3