If the straight line $(3 x + 4 y + 5) + k (x + 2 y - 3) = 0$ is parallel to x - axis then the value of $k$ is

1

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Solution

The correct option is A $- 3$

$(3 + k) x + (4 + 2 k) y + (5 - 3 k) = 0$

The line is parallel to the x-axis.

So, x-component $= 0$

$\Rightarrow 3 + k = 0$

$\Rightarrow k = - 3$

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