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Question

If the sum of first 10 natural numbers is S1 and that of first 10 whole numbers is S2. Then S1−S2 is

A
20
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B
10
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C
30
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D
40
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Solution

The correct option is B 10
The sets of natural and whole numbers are (1,2,3,4,5...) and (0,1,2,3...)

S1=n2(2a+(n1)d)=5(2+9)=55 and
S2=5((2×0)+9)=45
S1S2=5545=10

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