CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If the sum of n terms of an A.P. is 3n2+5n and Tm= 164, m=?


Solution

Tm = SmSm1 

 164 = 3m2 +5m - (3(m1)2​+5(m-1)) 

164 = 3 (2m-1) + 5.1  

   6m = 162  

 m = 27.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...



footer-image